#include <bits/stdc++.h>
using namespace std;
typedef vector<tuple<int, int, int>> vt;
typedef vector<pair<int, int>> vp;
// Input:
// Objects as (profit, weight, ratio) pairs
// objects[] = {{60, 10, 0}, {100, 20, 0}, {120, 30, 0}}
// Knapsack Capacity, M = 50;
// Output:
// Maximum possible profit = 240
// by taking objects of weight 10 and 20 kg and 2/3 fraction
// of 30 kg. Hence total profit will be 60+100+(2/3)(120) = 240
void profitByWeight(vt &objects)
{
for (int i = 0; i < objects.size(); i++)
{
get<2>(objects[i]) = get<0>(objects[i]) / get<1>(objects[i]);
}
}
bool sortByRatio(tuple<int, int, int> &a, tuple<int, int, int> &b)
{
return (get<2>(a) > get<2>(b));
}
void print(vp choice, int maxProfit)
{
cout << "Maximum possible profit = " << maxProfit << endl;
cout << "Weights\t"
<< "Profits" << endl;
for (int i = 0; i < choice.size(); i++)
{
cout << choice[i].first << '\t' << choice[i].second << endl;
}
}
void solution(vt objects, int M)
{
int maxProfit = 0;
vp choice;
for (int i = 0; i < objects.size(); i++)
{
if (M > 0 && get<1>(objects[i]) <= M)
{
M -= get<1>(objects[i]);
maxProfit += get<0>(objects[i]);
choice.push_back(make_pair(get<1>(objects[i]), get<0>(objects[i])));
}
else
{
int fraction = (M * get<0>(objects[i])) / get<1>(objects[i]);
maxProfit += fraction;
choice.push_back(make_pair(get<1>(objects[i]), fraction));
break;
}
}
print(choice, maxProfit);
}
int main()
{
vt objects;
objects.push_back(make_tuple(120, 30, 0));
objects.push_back(make_tuple(100, 20, 0));
objects.push_back(make_tuple(60, 10, 0));
int M = 50;
// Calculate profit/weight ratio
profitByWeight(objects);
// Sort in descending order of ratio
sort(objects.begin(), objects.end(), sortByRatio);
// Solution
solution(objects, M);
return 0;
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