// A Dynamic Programming based // solution for 0-1 Knapsack problem #include <bits/stdc++.h> using namespace std; // A utility function that returns // maximum of two integers int max(int a, int b) { return (a > b) ? a : b; } int knapSack(int M, int wt[], int val[], int n) { int K[n + 1][M + 1]; // Build table K[][] in bottom up manner for (int i = 0; i <= n; i++) { for (int j = 0; j <= M; j++) { if (i == 0 || j == 0) K[i][j] = 0; else if (wt[i] <= j) K[i][j] = max(K[i - 1][j], val[i] + K[i - 1][j - wt[i]]); else K[i][j] = K[i - 1][j]; } } return K[n][M]; } int main() { int val[] = { 0, 3, 4, 5, 6 }; // Array index to start from 1 int wt[] = { 0, 2, 3, 4, 5 }; // Array index to start from 1 int M = 8; int n = sizeof(val) / sizeof(val[0]); cout<< knapSack(M, wt, val, n); return 0; }
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C++ is a widely used middle-level programming language.
When ever you want to perform a set of operations based on a condition If-Else is used.
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