// C++ implementation to find the first negative
// integer in every window of size k
#include <bits/stdc++.h>
using namespace std;
// function to find the first negative
// integer in every window of size k
void printFirstNegativeInteger(int arr[], int n, int k)
{
// A Double Ended Queue, Di that will store indexes of
// useful array elements for the current window of size k.
// The useful elements are all negative integers.
deque<int> Di;
/* Process first k (or first window) elements of array */
int i;
for ( ; i < k; i++)
// Add current element at the rear of Di
// if it is a negative integer
if (arr[i] < 0)
Di.push_back(i);
// Process rest of the elements, i.e., from arr[k] to arr[n-1]
for (i=0 ; i < n; i++)
{
// if Di is not empty then the element at the
// front of the queue is the first negative integer
// of the previous window
if (!Di.empty())
cout << arr[Di.front()] << " ";
// else the window does not have a
// negative integer
else
cout << "0" << " ";
// Remove the elements which are out of this window
while ( (!Di.empty()) && Di.front() < (i - k + 1))
Di.pop_front(); // Remove from front of queue
// Add current element at the rear of Di
// if it is a negative integer
if (arr[i] < 0)
Di.push_back(i);
}
// Print the first negative
// integer of last window
if (!Di.empty())
cout << arr[Di.front()] << " ";
else
cout << "0" << " ";
}
// Driver program to test above functions
int main()
{
int arr[] = {12, -1, -7, 8, -15, 30, 16, 28};
int n = sizeof(arr)/sizeof(arr[0]);
int k = 3;
printFirstNegativeInteger(arr, n, k);
return 0;
}
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When ever you want to perform a set of operations based on a condition If-Else is used.
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