#include <iostream> #include <bits/stdc++.h> using namespace std; /** * Problem statement * Check if two strings are k-anagrams or not * * Given two strings of lowercase alphabets and a value K, your task is to complete the given function which tells if two strings are K-anagrams of each other or not. * * Two strings are called K-anagrams if both of the below conditions are true. * 1. Both have same number of characters. * 2. Two strings can become anagram by changing at most K characters in a string. * * ======================== * * Example input and output * * Input: str1="sun" str2="bun" k=1 * Output: true * * Input: str1="steam" str2="dream" k=2 * Output: true * * Input: str1="class" str2="green" k=2 * Output: false * * Input: str1="dog" str2="got" k=1 * Output: true * * Input: str1="right" str2="thing" k=1 * Output: true * * Input: str1="trick" str2="belt" k=5 * Output: false * * ========================= * * Task: * Just complete the given function `areKAnagrams` that * returns `true` if the strings can be turned into K-anagrams, * else return `false`. */ class Solution { public: bool areKAnagrams(string str1, string str2, int k) { int n1=str1.length; int n2=str2.length; if(n1!=n2) return false; sort(str1.begin().str1.end()); sort(str2.begin().str2.end()); for(int i=0;i<n1;i++) if(str1[i]!=str2[i]) return false; return true; } }; int main() { string str1, str2; cin>>str1>>str2; int k; cin>>k; Solution ob; if(ob.areKAnagrams(str1, str2, k) == true) cout<<"\n1"; else cout<<"\n0"; }
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C++ is a widely used middle-level programming language.
When ever you want to perform a set of operations based on a condition If-Else is used.
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You can also use if-else for nested Ifs and If-Else-If ladder when multiple conditions are to be performed on a single variable.
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