// A C++ program to find a peak element // using divide and conquer #include <bits/stdc++.h> using namespace std; // A binary search based function // that returns index of a peak element int findPeakUtil(int arr[], int low, int high, int n) { // Find index of middle element // (low + high)/2 int mid = low + (high - low) / 2; // Compare middle element with its // neighbours (if neighbours exist) if ((mid == 0 || arr[mid - 1] <= arr[mid]) && (mid == n - 1 || arr[mid + 1] <= arr[mid])) return arr[mid]; // If middle element is not peak and its // left neighbour is greater than it, // then left half must have a peak element else if (mid > 0 && arr[mid - 1] > arr[mid]) return findPeakUtil(arr, low, (mid - 1), n); // If middle element is not peak and its // right neighbour is greater than it, // then right half must have a peak element else return findPeakUtil( arr, (mid + 1), high, n); } // A wrapper over recursive function findPeakUtil() int findPeak(int arr[], int n) { return findPeakUtil(arr, 0, n - 1, n); } // Driver Code int main() { int arr[] = { 1, 3, 1,2,8,90,1, 0 }; int n = sizeof(arr) / sizeof(arr[0]); cout << "First Peak point is " << findPeak(arr, n); return 0; } // This code is contributed by rathbhupendra
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When ever you want to perform a set of operations based on a condition If-Else is used.
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