import java.util.*;

public class Main {
    public static void main(String[] args) {
      System.out.println("Hello, World!");
  }
}
/******************************************************************************

                            Online Java Compiler.
                Code, Compile, Run and Debug java program online.
Write your code in this editor and press "Run" button to execute it.

*******************************************************************************/

public class Main
{
	public static void main(String[] args) {
		System.out.println("Hello World");
	}
}
/******************************************************************************

                            Online Java Compiler.
                Code, Compile, Run and Debug java program online.
Write your code in this editor and press "Run" button to execute it.

*******************************************************************************/

public class Main
{
	public static void main(String[] args) {
		System.out.println("Hello World");
	}
}
                                 JAVA PROGRAM ON APPLETS AND PRODUCTION

import java.applet.Applet;  
import java.awt.Graphics;  
public class First extends Applet{  
  
public void paint(Graphics g){  
g.drawString("welcome",150,150);  
}  
 System.out.println(“array is out of range”);
Printf(“system is not correct”);
While
{
If else
Import java.util.scanner;
 Import util.math.language; 
}
class Adder{  
static int add(int a,int b){return a+b;}  
static int add(int a,int b,int c){return a+b+c;}  
}  
class TestOverloading1{  
public static void main(String[] args){  
System.out.println(Adder.add(11,11));  
System.out.println(Adder.add(11,11,11));  
}}  
}
temp = n;   
while(temp>0)   
{   
last = temp % 10;    
sum +=  (Math.pow(last, digits));   
temp = temp/10;   
temp = temp/10;
System.out.println(“the whole array is not in order”);
For(i=0;i<=n;i++
} 
class Adder{  
{
Int arr{a[0],a1[1],a2[2],a3[4]},i,j,k;
Int n;
Temp=0;
{
For(i=0;i<=n;i++)
{
System.out.println(“The array is in ascending order”);
System.out.println(“%d”,/n array is executed);
{
Scanf(“read all the inteers ”
import java.applet.Applet;  
import java.awt.Graphics;  
public class First extends Applet{  
  
public void paint(Graphics g){  
g.drawString("welcome",150,150);  
}  
 System.out.println(“array is out of range”);
Printf(“system is not correct”);
While
{
If else
Import java.util.scanner;
 Import util.math.language; 
}
class Adder{  
static int add(int a,int b){return a+b;}  
static int add(int a,int b,int c){return a+b+c;}  
}  
class TestOverloading1{  
public static void main(String[] args){  
System.out.println(Adder.add(11,11));  
System.out.println(Adder.add(11,11,11));  
}}  
}
 
1.	class Student3{  
2.	int id;  
3.	String name;  
4.	void display(){System.out.println(id+" "+name);}  
5.	public static void main(string[]args)  
6.	public static void main(String args[]){  
7.	Student3 s1=new Student3();  
8.	Student3 s2=new Student3();  
9.	s1.display();  
10.	s2.display();  
11.	}  
12.	}
    mysql> ALTER TABLE cats DROP gender;
Query OK, 0 rows affected (0.19 sec)
Records: 0 Duplicates: 0 Warnings: 0
mysql> DESCRIBE cats;
+-------+------------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------+------------------+------+-----+---------+----------------+
| id | int(10) unsigned | NO | PRI | NULL | auto_increment |
| name | varchar(150) | NO | | NULL | |
| owner | varchar(150) | NO | | NULL | |
| birth | date | NO | | NULL | |
+-------+------------------+------+-----+---------+----------------+
4 rows in set (0.00 sec)
See the Tutorial for more instructions on how to work with the MySQL server.
Other Important Tasks to Perform all the tasks and integers
The other arrays and existing arrays are also in the form of every negative arrays
The existing database should be very processed in every array and integer value
The existing and already existed database should be 

13.	           EXISTING DATABASE
14.	  MySQL> SHOW DATABASES;
          +-------------------+
          |Database           |
          +-------------------+
          |information schema |
          |performance        |
          +-------------------+
          |-------------------|
The database will decoded in the given arrays so that
every database will be stored in the existing MySQL database only
Once your MySQL server is up and running, you can connect to it as the superuser root with the
mysql client.
• On Linux, enter the following command at the command line terminal (for installation using generic
binaries, you might need to go first to the bin folder under the base directory of your MySQL
installation):
$> mysql -u root -p
• On Windows, click Start, All Programs, MySQL, MySQL 5.7 Command Line Client (or MySQL 8.0
Command Line Client, respectively). If you did not install MySQL with the MySQL Installer, open
a command prompt, go to the bin folder under the base directory of your MySQL installation, and
issue the following command:
C:\> mysql -u root -p
You are then asked for the root password, which was assigned in different manners according to the
way you installed MySQL. The installation and initialization instructions given above already explain the
root password, but here is a quick summary:
• For installations using the MySQL Yum repository, MySQL SUSE repository, or RPM packages
directly downloaded from Oracle, the generated root password is in the error log. View it with, for
example, the following command:
$> sudo grep 'temporary password' /var/log/mysqld.log
• For installations using the MySQL APT repository or Debian packages directly downloaded from
Oracle, you should have already assigned the root password yourself; if you have not done that for
some reason, see the "Important" note here or How to Reset the Root Password.
• For installations on Linux using the generic binaries followed by a data directory initialization using
mysqld --initialize as discussed in Initializing the Data Directory, the generated root
password is displayed in the standard error stream during the data directory's initialization:
[Warning] A temporary password is generated for root@localhost:
iTag*AfrH5ej
Note
Depending on the configuration you used to initialize the MySQL server, the
error output might have been directed to the MySQL error log; go there and
check for the password if you do not see the above message on your screen.
The error log is a file with a .err extension, usually found under the server's
data directory (the location of which depends on the server's configuration,
but is likely to be the data folder under the base directory of your MySQL
installation, or the /var/lib/mysql folder).
If you have initialized the data directory with mysqld --initialize-insecure instead, the root
password is empty.
The installation and decentralization will be decoded automatically in the arrays box and integers xxxxxxxxxxxxxxx
• For installations on Windows using the MySQL Installer and OS X using the installer package, yorself
Once you create the database then you will asked for the root password, which was assigned in different manners c
according to the way you installed MySQL.
The installation and intialization instructions given above already explain
the root password, 
*For installation using the MySQL yum repository, MySQL SUSE repository, or RPM packages
directly downloaded from Oracle, the generated root password is in the error log.
View it with, for
$> sudo grep 'temporary password' /var/log/mysqld.log
Oracle, you should have already assigned the root password yourself; if you have not done
The oracle should have already assigned the root and password which will automatically decoded.
                                       EXISTING Database
mysql> SHOW DATABASES;               mysql> SHOW DATABASEs;
+--------------------+               +-------------------+
| Database |                         |Database           |
+--------------------+               +-------------------+
| information schema |               |information schema |
| mysql |                            |Mysql              |
| performance_schema |               |performance_schema |
| pets |                             |system_schema      |
| sys |                              +-------------------+
                                     4 rows in set(0.00sec)
+--------------------+
5 rows in set (0.00 sec)

15.	 +-----------------| 
The existing database
Should be encoded and decoded at the same time then only the
remai 
1.	class Student5{  
2.	    int id;  
3.	    String name;  
4.	    int age;  
5.	    Student5(int i,String n)
6.	{  
7.	    id = i;  
8.	    name = n;  
9.	    }  
10.	   System.out.println(“array is in ascending order”);
11.	If array is not in order then the array will get disappeared 
12.	last = temp % 10;    
13.	sum +=  (Math.pow(last, digits));   
14.	temp = temp/10;   
15.	}
16.	    Student5(int i,String n,int a){  
17.	    id = i;  
18.	    name = n;  
19.	    age=a;  
20.	    }  
21.	    void display(){System.out.println(id+" "+name+" "+age);}  
22.	   
23.	    public static void main(String args[]){  
24.	    Student5 s1 = new Student5(111,"Karan");  
25.	    Student5 s2 = new Student5(222,"Aryan",25);  
26.	    s1.display();  
27.	    s2.display();  
28.	   }  
29.	}  

Output:
111 Karan 0
222 Aryan 25
________________________________________
Difference between constructor and method in Java
There are many differences between constructors and methods. They are given below.
Java Constructor	Java Method
A constructor is used to initialize the state of an object.
A constructor is used to divide the objects	A method is used to expose the behavior of an object.
A method is not used to divide the objects
A constructor must not have a return type.	A method must have a return type.
The constructor is invoked implicitly.
The constructor is not invoked implicity	The method is invoked explicitly.
The method is not invoked explicitly
The Java compiler provides a default constructor if you don't have any constructor in a class.	The method is not provided by the compiler in any case.
The constructor name must be same as the class name.
The constructor must be decoded very fastly
The older constructor must be oldest version than the newer version
For every constructor there is another class called constructor class	The method name may or may not be same as the class name.
The method name may or may not be same as the class name
The method cmust have a return type
For every method class there is very another class called method class
The constructor class must be in the same name as class name
The method class will be in the another side of the class name
The constructoe and method class will be same as another class
Constructor and method name is annoyed
For another set of arrays and integers 
This existing database is not in the array and that array will be existed already
To create the databse we should add all the array integers and non array integers also
MANAGER SERVICE PROVIDER:
------------------------
-->It is another part of the vms model
-->It advices and clients about the most effective responsive talent suppliers.
-->They generally donot recruite directly, but try to find the best suppliers of vendors according to 
the clients requirements
The constructor model should be same as another model


 
Java Copy Constructor
There is no copy constructor in Java. However, we can copy the values from one object to another like copy constructor in C++.
There are many ways to copy the values of one object into another in Java. They are:
o	By constructor
o	By assigning the values of one object into another
o	By clone() method of Object class
In this example, we are going to copy the values of one object into another using Java constructor.
class Student6
{
Class student()
Void public static main()
{
system.out.println("integer numbers are not displayed");
Int i=0,j=9,k;  
1.	    int id;  
2.	System.out.println(“string name is not correct”);
3.	
4.	    String name;  
5.	    Student6(int i,String n){  
6.	    id = i;  
7.	    name = n;  
8.	    }  
9.	    Constructior is not being displayed;

Constructor is not yet decided;  
10.	    Student6(Student6 s){  
11.	    id = s.id;  
12.	    name =s.name;  
13.	    }  
14.	    void display(){System.out.println(id+" "+name);}  
15.	   
16.	    public static void main(String args[]){  
17.	    Student6 s1 = new Student6(111,"Karan");  
18.	    Student6 s2 = new Student6(s1);  
19.	    s1.display();  
20.	    s2.display();  
21.	   }  
22.	}  
111 Karan
111 Karan
________________________________________
1.	class Student7
2.	{ 
3.	Temp=0;
4.	System.out.println(“array is not displayed”);
5.	Printf(“system array is not correct”); 
6.	    int id;  
7.	    String name;  
8.	    Student7(int i,String n){  
9.	    id = i;  
10.	    name = n;  
11.	    }  
12.	    Student7(){}  
13.	    void display(){System.out.println(id+" "+name);
14.	}  
15.	   Void display()
16.	Public static void main(string[]args)
17.	System.out.println(“given array is in ascending order”);
18.	
19.	    public static void main(String args[]){  
20.	    Student7 s1 = new Student7(111,"Karan");  
21.	    Student7 s2 = new Student7();  
22.	    s2.id=s1.id;  
23.	    System.out.println(“%d”,/n there is another integer and arrays called);
24.	    
25.	    s2.name=s1.name;  
26.	    s1.display();  
27.	    s2.display();  
28.	   }  
29.	} 
Output:
111 Karan
111 Karan

temp = n;   
while(temp>0)   
{   
last = temp % 10;    
sum +=  (Math.pow(last, digits));   
temp = temp/10;   
} 
class Adder{  
1.	Public static void main(string[] args)
2.	{  
3.	public static void main(String[] args)
4.	{  
5.	System.out.println(Adder.add(11,11));  
6.	System.out.println(Adder.add(12.3,12.6));  
7.	}
8.	}
9.	System.out.println(“the system number is not defined”);
10.	The functional array is not defined so that the numerial array is arranged in an order;
11.	System name is defined in a way that all the numbers are jumbled here and there;
12.	The whole process of decoding and executing is the method that should ekw
13.	If(num==sum)
14.	Number is not yet displayed;
15.	System.out.println(“int arg method invoked”);
16.	
17.	If system is not responding then that will be displayed automatically
18.	Return true;
19.	If else
20.	{
21.	Temp=0; 
1.	if(n==sum)   
2.	return true; 
3.	if else
1.	class OverloadingCalculation2
2.	{
3.	void sum(int a,int b)
4.	{
5.	System.out.println("int arg method invoked");
6.	}
7.	void sum(long a,long b)
8.	{
9.	System.out.println("long arg method invoked");
10.	}
11.	public static void main(String args[])
12.	{
13.	OverloadingCalculation2 obj=new OverloadingCalculation2();
14.	obj.sum(20,20)
15.	system.out.println(“system is out of range”);
16.	  }  
17.	}  
4.	Function to check whether the number is amrstrong or not
5.	If function is not correct the code is said to be debug
6.	System.out.println(“the array is out of bound”);
7.	Class overloadingcalculation()
8.	System.out.println(“array is out of range”);
9.	The java base should be very closer to the client and the programmer
10.	The programmer should be very easy so that the project should be very easy
11.	If else the program is incorrect then the client side must be defined correctly;
12.	When temp is empty then the array is not in descending order
13.	For given constructor the array is not in ascending order
14.	{
15.	System array is not in order;
16.	Functional array is not in order;
17.	Printf(“array is not in order”);
18.	System.printf(“array is in descending order”);
19.	Printf(“system is printed so easily”);
20.	System.out.println(“array printed successfully”);
21.	The given array and the array function is not defined here
22.	Given array is in not order 
23.	{
24.	 If else
25.	{
26.	Int i=7,j=9;
27.	Int arr={[a(10),a1(20)]};
28.	Int k,j;
29.	Flag=0
30.	{
31.	System.out.println(“array is out of range”);
32.	System.out.println(“%d”,n number is out of range);
33.	Return(0)    
34.	else return false;  
35.	else return false; 
36.	}   
37.	public static void main(String args[])     
38.	{     
39.	int num;   
40.	Scanner sc= new Scanner(System.in);  
41.	System.out.print("Enter the limit: ");  
42.	Reader reads from the user() 
43.	num=sc.nextInt();  
44.	number exits;
45.	System.out.println("Armstrong Number up to "+ num + " are: ");
46.	System.out.println(“Armstrong number up to” + num + “ are:”);
47.	System.our.println(“Armstrong number up to ”+num +” are:”);
48.	For system calling the array should be very defined and it should be very perfect;
49.	For function calling(“system is defined very clearly”);
50.	Function calling must be very order
51.	For(int i=0;i<=num;i++)  
52.	for(int i=0; i<=num; i++)  
53.	//function calling 
54.	Function is not considered for the string and for the file
55.	The function java is not defined so that It may be not defined
56.	Armstrong number is not defined in the program 
57.	The client may be not considered it as the perfect program
58.	System.out.println(“the system number is not defined”);
59.	The Armstrong number is not so strong
60.	if(isArmstrong(i))  
61.	System.out.print(i+ ", ");
62.	System.out.println(“Armstrong number is correct”);
63.	Function determination is not completed
64.	As of the loop is not considered the function is not determined
65.	  
66.	}    
67.	
68.	  
69.	Here the integer is in byte and character is alson in byte so that it will be easy to convert all the integers and 
        characters into the defined order
70.	Byte is considered as float character 
71.	All bytes are predefined
72.	Therefore:system.out.println(“array is printed perfectly”);
73.	The given program is not so correctly defined;
74.	{
75.	Therefore all the inputs which is given is not predefined;
76.	Function is not considered for the string and for the file
77.	The function java is not defined so that It may be not defined
78.	Armstrong number is not defined in the program;
79.	{
80.	The client may be not considered it as the perfect program
81.	System.out.println(“the system number is not defined”);
82.	The Armstrong number is not so strong
83.	if(isArmstrong(i))  
84.	System.out.print(i+ ", ");
85.	System.out.println(“Armstrong number is correct”);
86.	Function determination is not completed
87.	As of the loop is not considered the function is not determined
88.	  
89.	}   
90.	}  
Output:
Enter the limit: 999
Armstrong Number up to 999 are: 
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 153, 370, 371, 407
Let’s create another Java program that checks if the given number is an Armstrong number or not.
ArmstrongNumberExample2.java
1.	import java.util.Scanner;  
2.	import java.lang.Math;  
3.	public class ArmstsrongNumberExample2  
4.	{
The method must have the same name as in the parent class
The method must have the same parameter as in the parent class.
There must be an IS-A relationship (inheritance).
5.	
6.	static boolean isArmstrong(int n)   
7.	{   
8.	int temp, digits=0, last=0, sum=0;   
9.	temp=n;
10.	assign the variables in an ascending order;
11.	system.out.println(“arrange integers and variables in descending order”);
12.	loop execute until the condition becomes false   
13.	//loop execute until the condition becomes false  
14.	while(temp>0)    
15.	{   
16.	temp = temp/10;   
17.	digits++;   
18.	}   
19.	temp = n;   
20.	while(temp>0)   
21.	{   
22.	Browse the given numbers;
23.	For(i=0;i<=n;i++)
24.	{
25.	Last=temp%10;
26.	Temp==last digit;    
27.	last = temp % 10;
28.	calculate every sum of the value;
29.	therefore every array is arranged
30.	printf(“system is arranged in an order” );
31.	 system.out.println(arrange array in order that ascending order);
32.	Removes the last digit; 
33.	sum +=  (Math.pow(last, digits));
34.	sum + = (Math.pow(last, digits));   
35.	//removes the last digit  
36.	//removes the last digit 
37.	temp = temp/10;   
38.	}  
39.	//compares the sum with n  
40.	if(n==sum)   
41.	//returns if sum and n are equal  
42.	return true;      
43.	//returns false if sum and n are not equal  
44.	else return false;   
45.	}   
46.	//driver code 
1.	class OverloadingCalculation1{  
2.	  void sum(int a,long b){System.out.println(a+b);}  
3.	  void sum(int a,int b,int c){System.out.println(a+b+c);
4.	}  
5.	Void sum(int a,int b,int c){
6.	System.out.println(a+b+c);  
7.	  public static void main(String args[])
8.	{  
9.	  OverloadingCalculation1 obj=new OverloadingCalculation1();  
10.	  obj.sum(20,20);  
11.	  obj.sum(20,20,20);  
12.	  }  
13.	}   
47.	public static void  main(String args[])     
48.	{ 
1.	class OverloadingCalculation2{  
2.	  void sum(int a,int b){System.out.println("int arg method invoked");}  
3.	  void sum(long a,long b){System.out.println("long arg method invoked");}  
4.	  
5.	  public static void main(String args[]){  
6.	  OverloadingCalculation2 obj=new OverloadingCalculation2();  
7.	  obj.sum(20,20);//now int arg sum() method gets invoked  
8.	  }  
9.	}     
49.	int num;   
50.	Scanner sc= new Scanner(System.in);  
51.	System.out.print("Enter the number: ");  
52.	//reads the limit from the user  
53.	num=sc.nextInt();  
54.	if(isArmstrong(num))  
55.	{  
56.	System.out.print("Armstrong ");  
57.	}  
58.	else   
59.	{  
60.	System.out.print("Not Armstrong ");  
61.	}  
62.	}   
63.	}  
Output 1:
Enter the number: 2
Armstrong
Output 2:
Enter the number: 1675
Not Armstrong
________________________________________
array={a0[1]a1[2]a2[3]a3[4]......a8}
if else
System.out.println("/the array will get printed");
array={a[char=0],a1[int=1],a2[temp]}
System.out.println("char,int,temp will be printed");
printf("%d,/n");
for(i=0;i<=n;i++)
{
array=char+int;
temp=0;
int=char(varchar);

("Machine operator" or "lift operator")