-- create
CREATE TABLE airbnb_listings (
  id INTEGER PRIMARY KEY,
  city TEXT NOT NULL,
  country TEXT NOT NULL,
  number_of_rooms INTEGER NOT NULL, 
  year_listed INTEGER NOT NULL
);

-- insert
INSERT INTO airbnb_listings VALUES (0001, 'Paris', 'France', 5, 2018);
INSERT INTO airbnb_listings VALUES (0002, 'Tokyo', 'Japan', 2, 2017);
INSERT INTO airbnb_listings VALUES (0003, 'New York', 'USA', 2, 2022);


-- QUERYING TABLES 

-- Get all the columns from a table 
SELECT * 
FROM airbnb_listings;


-- Return the city column from the table
-- SELECT city 
-- FROM airbnb_listings;


-- Get the city and year_listed columns from the table
-- SELECT city, year_listed
-- from airbnb_listings;


-- Get the listing id, city, ordered by the number_of_rooms in ascending order
-- SELECT id, city
-- FROM airbnb_listings
-- ORDER BY number_of_rooms ASC;


-- Get the listing id, city, ordered by the number_of_rooms in descending order
-- SELECT id, city
-- FROM airbnb_listings
-- ORDER BY number_of_rooms DESC;


-- Get the first 5 rows from the airbnb_listings table
-- SELECT * 
-- FROM airbnb_listings
-- LIMIT 5;


-- Get a unique list of cities wehre there are listings 
-- SELECT DISTINCT city
-- FROM airbnb_listings;





-- FILTERING DATA 

-- Get all the listings wehre number_of_rooms is more or equal to 3
-- SELECT * 
-- FROM airbnb_listings
-- WHERE number_of_rooms >= 3;


-- Get all the listings where number_of_rooms is more than 3
-- SELECT *
-- FROM airbnb_listings
-- WHERE number_of_rooms > 3;


-- Get all the listings where number_of_rooms is exactly equal to 2
-- SELECT *
-- FROM airbnb_listings
-- WHERE number_of_rooms = 2;


-- Get all the listings with 3 to 6 rooms
-- SELECT *
-- FROM airbnb_listings
-- WHERE number_of_rooms BETWEEN 3 AND 6;


-- Get all the listings that are based in 'Paris'
-- SELECT * 
-- FROM airbnb_listings
-- WHERE city = 'Paris';


-- Get the listings based in the 'USA' and in 'France'
-- SELECT * 
-- FROM airbnb_listings
-- WHERE country IN ('USA', 'France');


-- Get all the listings where the country starts with 'j' and wehre the country does not end in 't'
-- SELECT *
-- FROM airbnb_listings
-- WHERE country LIKE 'j%' AND country NOT LIKE '%t';


-- Get all the listings in 'Paris' wehre number_of_rooms is bigger than 3  
-- SELECT * 
-- FROM airbnb_listings
-- WHERE city = 'Paris' AND number_of_rooms > 3;


-- Get all the listings in 'Paris' OR the ones that were listed after 2012
-- SELECT *
-- FROM airbnb_listings
-- WHERE city = 'Paris' OR year_listed > 2012


-- Return the listings where number_of_rooms is missing 
-- SELECT *
-- FROM airbnb_listings
-- WHERE number_of_rooms IS NULL;


-- Return the listings wehre number_of_rooms is not missing 
-- SELECT * 
-- FROM airbnb_listings
-- WHERE number_of_rooms IS NOT NULL;







-- AGGREGATING DATA 

-- Get the total number of rooms available across all listings 
-- SELECT SUM(number_of_rooms)
-- FROM airbnb_listings;


-- Get the average number of rooms per listing across all listings 
-- SELECT AVG(number_of_rooms)
-- FROM airbnb_listings;


-- Get the listing with the highest number of rooms across all listings 
-- SELECT MAX(number_of_rooms)
-- FROM airbnb_listings;


-- Get the total number of rooms for each country
-- SELECT country, SUM(number_of_rooms)
-- FROM airbnb_listings
-- GROUP BY country;


-- Get the average number of rooms for each country
-- SELECT country, AVG(number_of_rooms)
-- FROM airbnb_listings
-- GROUP BY country;


-- For each country, get the average number of rooms per listing, sorted by ascending order 
-- SELECT country, AVG(number_of_rooms) AS avg_rooms
-- FROM airbnb_listings
-- GROUP BY country
-- ORDER BY avg_rooms ASC;


-- For Japan and the USA, get the average numbner of rooms per listing in each country
-- SELECT country, AVG(number_of_rooms)
-- FROM airbnb_listings
-- WHERE country IN ('USA', 'JAPAN')
-- GROUP BY country;


-- Get the number of cities per country, where there are listings 
-- SELECT country, COUNT(city) AS number_of_cities 
-- FROM airbnb_listings
-- GROUP BY country;


-- Get all the years where there were more than 100 listings per year 
-- SELECT year_listed
-- FROM airbnb_listings
-- GROUP BY year_listed
-- HAVING COUNT(year_listed) > 100;











































 
by

MySQL online editor

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About MySQL

MySQL is a open-source, free and very popular relational database management system which is developed, distributed and supported by Oracle corporation.

Key Features:

  • Open-source relational database management systems.
  • Reliable, very fast and easy to use database server.
  • Works on client-server model.
  • Highly Secure and Scalable
  • High Performance
  • High productivity as it uses stored procedures, triggers, views to write a highly productive code.
  • Supports large databases efficiently.
  • Supports many operating systems like Linux*,CentOS*, Solaris*,Ubuntu*,Windows*, MacOS*,FreeBSD* and others.

Syntax help

Commands

1. CREATE

CREATE TABLE table_name (
                column1 datatype,
                column2 datatype,
                ....);

Example

CREATE TABLE EMPLOYEE (
  empId INTEGER PRIMARY KEY,
  name TEXT NOT NULL,
  dept TEXT NOT NULL
);

2. ALTER

ALTER TABLE Table_name ADD column_name datatype;

Example

INSERT INTO EMPLOYEE VALUES (0001, 'Dave', 'Sales');

3. TRUNCATE

TRUNCATE table table_name;

4. DROP

DROP TABLE table_name;

5. RENAME

RENAME TABLE table_name1 to new_table_name1; 

6. COMMENT

Single-Line Comments:

 --Line1;

Multi-Line comments:

   /* Line1,
   Line2 */

DML Commands

1. INSERT

INSERT INTO table_name (column1, column2, column3, ...) VALUES (value1, value2, value3, ...);

Note: Column names are optional.

Example

INSERT INTO EMPLOYEE VALUES (0001, 'Ava', 'Sales');

2. SELECT

SELECT column1, column2, ...
FROM table_name
[where condition]; 

Example

SELECT * FROM EMPLOYEE where dept ='sales';

3. UPDATE

UPDATE table_name
SET column1 = value1, column2 = value2, ...
WHERE condition; 

Example

UPDATE EMPLOYEE SET dept = 'Sales' WHERE empId='0001'; 

4. DELETE

DELETE FROM table_name where condition;

Example

DELETE from EMPLOYEE where empId='0001'; 

Indexes

1. CREATE INDEX

  CREATE INDEX index_name on table_name(column_name);
  • To Create Unique index:
  CREATE UNIQUE INDEX index_name on table_name(column_name);

2. DROP INDEX

DROP INDEX index_name ON table_name;

Views

1. Create a View

Creating a View:
CREATE VIEW View_name AS 
Query;

2. How to call view

SELECT * FROM View_name;

3. Altering a View

ALTER View View_name AS 
Query;

4. Deleting a View

DROP VIEW View_name;

Triggers

1. Create a Trigger

CREATE TRIGGER trigger_name trigger_time trigger_event
    ON tbl_name FOR EACH ROW [trigger_order] trigger_body
/* where
trigger_time: { BEFORE | AFTER }
trigger_event: { INSERT | UPDATE | DELETE }
trigger_order: { FOLLOWS | PRECEDES } */

2. Drop a Trigger

DROP TRIGGER [IF EXISTS] trigger_name;

Stored Procedures

1. Create a Stored Procedure

CREATE PROCEDURE sp_name(p1 datatype)
BEGIN
/*Stored procedure code*/
END;

2. How to call Stored procedure

CALL sp_name;

3. How to delete stored procedure

DROP PROCEDURE sp_name;

Joins

1. INNER JOIN

SELECT * FROM TABLE1 INNER JOIN TABLE2 where condition;

2. LEFT JOIN

SELECT * FROM TABLE1 LEFT JOIN TABLE2 ON condition;

3. RIGHT JOIN

SELECT * FROM TABLE1 RIGHT JOIN TABLE2 ON condition;

4. CROSS JOIN

SELECT select_list from TABLE1 CROSS JOIN TABLE2;