How to find Armstrong no or not in java by jayanthi ganesh

import java.util.*;

public class Armstrong {

public static void main(String[] args) {

    int number = 153, originalNumber, remainder, result = 0;

    originalNumber = number;

    while (originalNumber != 0)
    {
        remainder = originalNumber % 10;
        result += Math.pow(remainder, 3);
        originalNumber /= 10;
    }

    if(result == number)
        System.out.println(number + " is an Armstrong number.");
    else
        System.out.println(number + " is not an Armstrong number.");
}

}