Ignore falsy values

Problem Description
Sam is a very optimistic lad. He does not like anything which is false in nature. You will be given an array arr as an argument. You have to implement the function removeFalsyValues which removes all the elements and returns a new array that does not contain any falsy values.

Hint 1: Falsy values in JavaScript are false, null, 0, "", ‘’, undefined, and NaN.

Hint 2: Create a new array, use a conditional statement along logical operators to check if the element is falsy or not, and accordingly push that element into the array.

Sample Input 1
7, ate, "", false, 9

Sample Output 1
7, ate, 9

Explanation
"" and false are falsy values. Thus the returned array is 7, ate, 9.

Sample Input 2
a, b, c

Sample Output 2
a, b, c

Explanation
None of the values in the array are falsy. Thus the returned array is the same as the given array, i.e a, b, c

/**
 * @param {string[]} arr
 * @return {string[]}
 */


function removeFalsyValues(arr) {
  // You only need to implement this function.
}

if (removeFalsyValues([1,2,3]).toString()!== [ 1, 2, 3 ].toString())
  console.log("Test fails: Expected [1, 2, 3] for input arr = [1, 2, 3]");
else
  console.log("Sample test case for input arr = [1, 2, 3] passed!");

module.exports = removeFalsyValues