Find Even and Odd number in an array without using javascript method ?

const numbers = [1,2,3,4,5,6,7,8,9,10];
const evenNumbers=[];
const oddNumbers=[];

function findOddEvenNumbers(arr) {
for(let i=0; i<arr.length; i++){
if(arr[i] % 2 ===0){
evenNumbers.push(arr[i]);
}

if(arr[i] % 2 !==0){
  oddNumbers.push(arr[i])
}

}
console.log("Odd number :", oddNumbers);
console.log("Even number :", evenNumbers);
}

findOddEvenNumbers(numbers)