How do I square every digit of a number in Python

3342 

def squares(num):
    s = 0
    for i in str(num):
        y = int(i) * int(i)
        s += y 
    return s

I'm trying to square each digit of a number as shown below. How ever, i'm getting the output as 162 when i pass input as 99 instead of expected output 8181. Any suggestions?

2 Answers

4 years ago by

Since you are adding the integers, it automatically performs addition. If you append the data as a string, you can get the expected output as 8181 like below

def squares(num):
    s = 0
    for i in str(num):
        y = int(i) * int(i)
        s += str(y) 
    return s
4 years ago by Divya
num = input("enter a number to get its square")
s = num ** 2
print(f"the square of {num} is {s}")
1 year ago by Rodaina