Please Give Coding For find the leap Year

y=int(input("Enter A Year:"))
if y%4==0:
print("Leap Year")
else:
print("Not A Leap Year")

CSharp, plus this is more accurate.

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text.RegularExpressions;

namespace HelloWorld
{
	public class Program
	{
		public static void Main(string[] args)
		{
			int year = Convert.ToInt32(Console.ReadLine());
			bool leap = true;
			
			if(year % 4 == 0)
			{
			  if(year % 100 == 0)
			  {
			    leap = false;
			    if(year % 400 == 0)
			    {
			      leap = true;
			    }
			  }
		  }else
		  {
		    leap = false;
		  }
		  if(leap == true)
		  {
		    Console.WriteLine("yes");
		    return;
		  }
		  Console.WriteLine("no");
	  }
  }
}

A simple solution in Python:
year = int(input())
if (year%4==0 and year%100!=0) or (year%400==0):
print("{0} is leap".format(year))
else:
print("{0} isn't leap".format(year))

I'll be sending a C++ solution.

 #include <iostream>
 using namespace std;
 
 int main(){
   int year;
   cin >> year;
   if(year % 4 == 0){
     cout << "The given year is a leap year." << endl;
   }else{
     cout << "The given year is NOT a leap year." << endl;
   }
   return 0;
 }

• All the best, Quillsh Wammy.