Determination of whether a number is even or odd (use of conditional statement)
Determination of whether a number is even or odd (use of conditional statement)
2 Answers
2 years ago by Alhassan Nasiru
| column 1 | column 2 |
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#
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|---|---|
| row 1 value 1 | row 1 value 2 |
| row 2 value 2 | row 2 value 2 |
2 years ago by Ankit Kumar
Using JavaScript
function checkEvenOrOdd(number) {
if (number % 2 === 0) {
console.log(number + " is even");
} else {
console.log(number + " is odd");
}
}
// Example usage:
checkEvenOrOdd(4); // Output: 4 is even
checkEvenOrOdd(7); // Output: 7 is odd
1 year ago by Sandeep Chauhan