/* 001 Two Number Sum Write a function that takes in a non-empty array of distinct integers and an integer representing a target sum. If any two numbers in the input array sum up to the target sum, the function should return them in an array, in any order. If no two numbers sum up to the target sum, the function should return an empty array. Note that the target sum has to be obtained by summing two different integer in the array; you can't add a single integer to itself in order to obtain the target sum. You can assume that there will be at most one pair of numbers summing up to the target sum. Sample Input array = [3, 5, -4, 8, 11, 1, -1, 6] targetSum = 10 Sample Output (the numbers could be in reversed order) [-1, 11] */ #include <vector> #include <unordered_set> #include <iostream> #include <algorithm> using namespace std; // O(n) time | O(n) space vector<int> twoNumberSum(vector<int> inputArray, int targetSum) { unordered_set<int> nums; for (int num: inputArray) { int potentialMatch = targetSum - num; if (nums.find(potentialMatch) != nums.end()) { return vector<int>{potentialMatch, num}; } else { nums.insert(num); } } return {}; } // test int main(int argc, char** argv) { int targetSum = 10; vector<int> inputArray = {3, 5, -4, 8, 11, 1, -1, 6}; vector<int> outputArray = twoNumberSum(inputArray, targetSum); bool sizeCheck = outputArray.size() == 2; bool memberCheck1 = count(outputArray.begin(), outputArray.end(), -1); bool memberCheck2 = count(outputArray.begin(), outputArray.end(), 11); cout << boolalpha << sizeCheck << endl << memberCheck1 << endl << memberCheck2 << endl; // end of main func return 0; }
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When ever you want to perform a set of operations based on a condition If-Else is used.
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